SOLUTION: The manager of a coffee shop has one type of coffee that sells for $8 per pound and another that sells for $15 per pound. The manager wishes to mix 60 pounds of the $15 coffee to g

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: The manager of a coffee shop has one type of coffee that sells for $8 per pound and another that sells for $15 per pound. The manager wishes to mix 60 pounds of the $15 coffee to g      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 532246: The manager of a coffee shop has one type of coffee that sells for $8 per pound and another that sells for $15 per pound. The manager wishes to mix 60 pounds of the $15 coffee to get a mixture that will sell for $14 per pound. How many pounds of the $8 coffee should be used?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of $8 coffee needed
given:
+60%2A15+=+900+ is cost of $15 coffee
+8x+ = cost of $8 coffee
+60+%2B+x+ = total pounds of coffee in mixture
-----------
+%28+900+%2B+8x+%29+%2F+%28+60+%2B+x+%29+=+14+
+900+%2B+8x+=+14%2A%28+60+%2B+x+%29+
+900+%2B+8x+=+840+%2B+14x+
+6x+=+900+-+840+
+6x+=+60+
+x+=+10+
10 pounds of $8 coffee are needed
check:
+%28+900+%2B+8x+%29+%2F+%28+60+%2B+x+%29+=+14+
+%28+900+%2B+8%2A10+%29+%2F+%28+60+%2B+10+%29+=+14+
+980+%2F+70+=+14+
+980+=+80+
OK