SOLUTION: A foundry needs to produce 75 tons of an alloy that is 34% copper. It has supplies of 9% copper and 84% copper alloy. How many tons of each must be mixed obtain he desired results
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Question 529692: A foundry needs to produce 75 tons of an alloy that is 34% copper. It has supplies of 9% copper and 84% copper alloy. How many tons of each must be mixed obtain he desired results Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A foundry needs to produce 75 tons of an alloy that is 34% copper. It has supplies of 9% copper and 84% copper alloy.
How many tons of each must be mixed obtain he desired results
:
Let x = amt of 84% copper required
then the total is required to be 75 tons, therefore
(75-x) = amt of 9% copper required
:
A typical mixture equation,
:
.84x + .09(75-x) = .34(75)
.84x + 6.75 - .09x = 25.5
.84x - .09x = 25.5 - 6.75
.75x = 18.75
x =
x = 25 tons of 84% copper
then
75 - 25 = 50 tons of 9% copper
:
:
Check this is
.84(25) + .09(50) = .34(75)
21 + 4.5 = 25.5
