SOLUTION: Question: How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid?
Answer Options: A. 11.2gal C.112gal
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Answer Options: A. 11.2gal C.112gal
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Question 523532: Question: How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid?
Answer Options: A. 11.2gal C.112gal
B.208gal D.None of these<----wrong answer(known)
Tried: .5x+80(.14)=.40
.14+.40=.5x Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! How much of a 50% acid solution must be mixed with 80 gallons of a 14% acid solution to obtain a solution that is 40% acid?
:
Where x is amt of 50% solution required, the equation should be
.50x + .14(80) = .40(x+80)
