SOLUTION: You need a 40% alcohol solution. On hand, you have a 650 mL of a 20% alcohol mixture. You also have 90% alcohol mixture. How much of the 90% mixture will you need to add to obtain
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Question 522149: You need a 40% alcohol solution. On hand, you have a 650 mL of a 20% alcohol mixture. You also have 90% alcohol mixture. How much of the 90% mixture will you need to add to obtain the desired solution?
You will need
mL of the 90% solution
to obtain
mL of the desired 40% solution. Found 2 solutions by mananth, lowtek:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! --------percent ---------------- quantity
Alcohol Type I 20 ---------------- 650 ml
Alcohol type II 90 ---------------- x ml
Mixture 40 ---------------- 650 + x ml
20*650+90x=40(650+x)
13000+90x=26000 +40x
90x-40x =26000-( -13000)
50x=13000
/50
x= 260
260 ml of Alcohol type II (90%)
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