SOLUTION: You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
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Question 521471: You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
You will need
mL of pure water
to obtain
mL of the desired 80% solution. Found 2 solutions by stanbon, richwmiller:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You need a 80% alcohol solution. On hand, you have a 320 mL of a 85% alcohol mixture. How much pure water will you need to add to obtain the desired solution?
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Equation:
alcohol + alcohol = alcohol
0.85*320 + 0*x = 0.80(320+x)
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Multiply thru by 100 to get:
85*320 + 0 = 80*320 + 80x
5*320 = 80x
x = 20 mL (amt. of pure water needed)
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Cheers,
Stan H.
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You can put this solution on YOUR website! from the view of water
320*.15+w=(320+w)*.20
w=20 ml of water
from the view of alcohol
.85*320=.80*(320+w)
w=20 ml of water
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