SOLUTION: how many liters of a mixture containing 80% alcohol solution should be added to 5 liters of a 20% solution to yield a 30% solution?

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Question 514329: how many liters of a mixture containing 80% alcohol solution should be added to 5 liters of a 20% solution to yield a 30% solution?
Answer by mathstutor494(120) About Me  (Show Source):
You can put this solution on YOUR website!
Let mixture containing 80% alcohol solution be : x litres
Therefore
x*0.8 + 5*0.2 = 0.3(x+5)
Solving above eqn we get x= 1 Litre