Question 510304: chemical is 60% acid and chemical B is 36% acid. How much of each should be mixed together to get 120oz of a chemical that is 52% acid?
Answer by oberobic(2304)   (Show Source):
You can put this solution on YOUR website! With mixture problems, you need to keep track of how much 'pure' stuff you have or need.
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120 oz. of a 52% solution means you need to have .52*120 = 62.4 oz of 'pure' acid in the 120 oz.
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You will combine an unknown amount of one solution, 'x' with another amount to have 120 oz.
So we can use x' and '120-x' as the two volumes.
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The combined solutions are defined by the following equation.
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60%*x + 36%(120-x) = 52%*120
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Solve it.
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.60x + .36(120-x) = .52*120
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multiply by 100 to eliminate decimals
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60x + 36(120-x) = 52*120
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60x +4320 -36x = 6240
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24x = 6240 -4320
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24x = 1920
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x = 80 oz
120-x = 40 oz
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Answer: Combine 80 oz. of 60% solution and 40 oz. of 36% solution.
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Check to be sure the answer is right.
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60%(80 oz) = 48 oz of 'pure' acid
36%(40 oz) = 14.4 oz of 'pure' acid
48 + 14.4 = 62.4 oz. of 'pure' acid in the 120 oz., which is what we need to achieve 52%
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Done.
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