SOLUTION: A chemist has two solutions H2SO4. One has a 40% concentration and the other one has a 25% concentration. How many liters of each solution must be mixed to obtain 106 liters of a 3
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Question 508089: A chemist has two solutions H2SO4. One has a 40% concentration and the other one has a 25% concentration. How many liters of each solution must be mixed to obtain 106 liters of a 36% solution? Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website! Solution A
Amount = x liters
Concentration =40% = 0.40
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Solution B
Amount =(106- x) liters
Concentration =25% = 0.25
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Resultant Solution
Amount = 106 liters
Concentration = 36%=0.36
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[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
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Put the value in above equation
(x*0.40)+((106-x)*0.25=106*0.36
0.40x+26.5-0.25x=38.16
0.15x=38.16-26.5
0.15x=11.66
Divide by 0.15 both sides
0.15x/0.15=11.66/0.15
x=77.73
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Amount of solution A = 77.73 liters
Amount of Sultion B = 106-77.73=28.27 liters
