Question 507315: How many quarts of water [0% alcohol] need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution? Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many quarts of water [0% alcohol] need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?
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Equation:
water + water = water
x + 0.20*50 = 0.90(x+50)
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Multiply thru by 100 to get:
100x + 20*50 = 90x + 90*50
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10x = 70*50
x = 350 quarts (amt. of water needed)
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Cheers,
Stan H.
You can put this solution on YOUR website! How many quarts of water [0% alcohol] need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?
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let x=quarts of water to be added
80%*50+0%x=10%(50+x)
40+0=5+.1x
40-5=.1x
35=.1x
x=350 quarts
ans:
350 quarts of water need to be added to 50 quarts of 80% alcohol to obtain a 10% alcohol solution?
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