SOLUTION: Suppose that X liters of 38% acid solution are mixed with y liters of a 42% solution to obtain 100L of a 39% solution. One equation in a system for solving this problem is x+y=100.

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Question 505302: Suppose that X liters of 38% acid solution are mixed with y liters of a 42% solution to obtain 100L of a 39% solution. One equation in a system for solving this problem is x+y=100. Which one of the following is the other equation? A. 42x+38y=0.39*100 B 0.38x+0.42y=0.39*100 C. 0.42x+0.38y=0.39*100 D. 38x+42y=39
Answer by stanbon(75887) About Me  (Show Source):
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Suppose that X liters of 38% acid solution are mixed with y liters of a 42% solution to obtain 100L of a 39% solution. One equation in a system for solving this problem is x+y=100.

Which one of the following is the other equation?
A. 42x+38y=0.39*100
B 0.38x+0.42y=0.39*100
C. 0.42x+0.38y=0.39*100
D. 38x+42y=39
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Ans: B
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Cheers,
Stan H.
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