SOLUTION: A car radiator contains 10quarts of a 30% anitfreeze solution. How many quarts will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze

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Question 503240: A car radiator contains 10quarts of a 30% anitfreeze solution. How many quarts will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A car radiator contains 10 quarts of a 30% anitfreeze solution. How many quarts will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze
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Equation:
alcohol - alcohol + alcohol = alcohol
0.30*10 - 0.30x + 1.00x = 0.50*10
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Multiply thru by 100 to get:
30*10 - 30x + 100x = 50*10
70x = 20*10
x = (1/7)20
x = (20/7) quarts (amt. of 10% solution to replace by 100% antifreeze)
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Cheers,
Stan H.