Question 498997: Given the numbers 1 - 9; arrange them so that the sum of two 3-digit numbers equals a 3 digit number Found 2 solutions by chessace, elrazky1:Answer by chessace(471) (Show Source):
You can put this solution on YOUR website! Cool problem!
Can't be done!
Sum 1 to 9 is 45.
The sum of all the digits of the 1st two 3 digit numbers + possible carry=
sum of 3 "answer" digits.
If there is no carry, these 2 "equal" sums add to an even number, not 45.
So there must be a carry.
And the "answer" digits must sum to 23.
Only way is 9 8 6 and to get a carry, 9 would have to be on top too.
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