You can put this solution on YOUR website! How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 95% antifreeze?
:
Let w = amt of water (gal) required to accomplish this
1 = .95(w+1)
1 = .95w + .95
1 - .95 = .95w
.05 = .95w
w =
w = .0526 gal of water