SOLUTION: A 10-lb bag of mixed nuts contains 20% peanuts. How many pounds of peanuts should be added to change the mixture to 80% peanuts?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A 10-lb bag of mixed nuts contains 20% peanuts. How many pounds of peanuts should be added to change the mixture to 80% peanuts?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 491167: A 10-lb bag of mixed nuts contains 20% peanuts. How many pounds of peanuts should be added to change the mixture to 80% peanuts?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of peanuts to be added
+.2%2A10+=+2+ pounds of peanuts in 10 pound bag
In words:
(final pounds of peanuts) / (final pounds of mixture) = 80%
+%28+2+%2B+x+%29+%2F+%28+10+%2B+x+%29+=+.8+
+2+%2B+x+=+.8%2A%28+10+%2B+x+%29+
+2+%2B+x+=+8+%2B+.8x+
+.2x+=+8+-+2+
+.2x+=+6+
+x+=+30+
30 pounds of peanuts should be added
check:
+%28+2+%2B+x+%29+%2F+%28+10+%2B+x+%29+=+.8+
+%28+2+%2B+30+%29+%2F+%28+10+%2B+30+%29+=+.8+
+32+%2F+40+=+.8+
+32+=+32+
OK