SOLUTION: Mike is a chemist. He needs to prepare 36 ounces of 13% hydrochloric acid solution. Find the amount of 18% solution and amount of 9% solution he should mix to get this solution.

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Question 479334: Mike is a chemist. He needs to prepare 36 ounces of 13% hydrochloric acid solution. Find the amount of 18% solution and amount of 9% solution he should mix to get this solution.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
He needs to prepare 36 ounces of 13% hydrochloric acid solution.
Find the amount of 18% solution and amount of 9% solution he should mix to get this solution.
:
Let x = amt of 18% solution required
the total is given as 36 oz, therefore:
(36-x) = 9% solution required
;
A typical mixture equation
.18x + .09(36-x) = .13(36)
.18x + 3.24 - .09x = 4.68
.18x - .09x = 4.68 - 3.24
.09x = 1.44
x = 1.44%2F.09
x = 16 oz of 18% acid required
then
36 - 16 = 20z of 9% acid
:
:
Check the solution in the original equation
.18(16) + .09(20) = .13(36)