SOLUTION: A certain of beer is 5% alcohol and another type of beer is 2% alcohol. How much of each type should be mixed to get 100L of beer which is 3.2% alcohol?

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Question 47437This question is from textbook
: A certain of beer is 5% alcohol and another type of beer is 2% alcohol. How much of each type should be mixed to get 100L of beer which is 3.2% alcohol? This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
.05X+.02(100-X)=.032*100 OR .05X+2-.02X=3.2 OR .03X=1.2 OR X=1.2/.03 OR X=40L OF 5%
& 100-40=60L OF 2%
PROOF 40*.05+60*.02=100*.032 OR 2+1.2=3.2 OR 3.2=3.2