SOLUTION: How many liters of 50% acid must be mixed with 20% acid to get 10 liters of a 30% mixture?

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Question 470909: How many liters of 50% acid must be mixed with 20% acid to get 10 liters of a 30% mixture?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

get 10 liters 

Let x and (10L-x) represent the amounts of the 50% and 20% solutions respectively

Mixing

  .5x + .2(10L-x) = .30*10L

        .3x = .28*10L

          x = 9 1/3L of 50% and 2/3L of the 20% need to be mixed