SOLUTION: 2) How many Liters each of 15% acid and 33% acid should be mixed to get 120 Liters of 21% acid?

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Question 469447: 2) How many Liters each of 15% acid and 33% acid should be mixed to get 120 Liters of 21% acid?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

mixed to get 120 Liters 

Let x and (120-x) represent the amount of the  33% and 15% solutions respectively

Question states*** 

 mixing to get 120 Liters of 21% acid?

   .33x + .15(120-x) = .21*120L

Solving for x

     .18x  = .06*120L =  7.2L

      x = 40L, the amount of the 33% Solution.  80L of the 15% solution



CHECKING our Answer***

  .33*40 + .15*80 = 13.2 + 12 = 25.2 = .21*120