SOLUTION: an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze m
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Question 466529: an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! an automobile director contains 8 liters of solution that 10% is antifreeze. How many liters of water must be drained and replaced with pure antifreeze to obtain a 25% antifreeze mixture?
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let x=liters of 10% solution that must be drained and replaced with pure antifreeze.
8-x =liters of remaining 10% solution
100%x+10%(8-x)=25%(8)
x+.8-.1x=2
.9x=1.2
x=1.33 liters
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