Question 447846: How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many liters of 60% solution of sulfuric acid should be added to 10 liters of a 30% solution of sulfuric acid to obtain a 50% solution?
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acid + acid = acid
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0.60x + 0.30*10 = 0.50(x+10)
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Multiply thru by 100 to get:
60x + 30*10 = 50x + 50*10
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10x = 20*10
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x = 20 liters (amt. of 60% solution:
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Cheers,
Stan H.
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