Question 447012: I have some 40% solution of alcohol and some pure alcohol. How much of each must I mix to get 60 ounces of a 50% solution? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! .4x+1(60-x)=30
.4x+60-x=30
60-.6x=30
30=.6x
30/.6=x=50
You need 50 ozs. of 40% solution and 10 ozs. of 100% solution to get 60 ozs. of 50% solution..