SOLUTION: Tank A contains a mixture of 10 gallons water& 5 gallons pure alcohol.Tank B has 12 gallons water& 3 gallons pure alcohol.How many gallons should be taken from each tank and combin

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Question 445909: Tank A contains a mixture of 10 gallons water& 5 gallons pure alcohol.Tank B has 12 gallons water& 3 gallons pure alcohol.How many gallons should be taken from each tank and combined in order to obtain 8 gallon soln containing 25%alchl by vol...?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Tank A contains a mixture of 10 gallons water & 5 gallons pure alcohol.
50% alcohol
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Tank B has 12 gallons water& 3 gallons pure alcohol.
25% alcohol
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How many gallons should be taken from each tank and combined in order to obtain 8 gallon solution containing 25% alcohol by vol...?
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Equation:
alcohol + alcohol = alcohol
0.50x + 0.25(8-x) = 0.25*8
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You could work the equation and find x = 0
or you could see it's obvious that you
would take none of the 50% solution and 8 gallons
of the 25% solution.
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Here's the math:
0.50x + 0.25(8-x) = 0.25*8
Multiply thru by 100 to get:
50x + 25*8 - 25x = 25*8
25x = 0
x = 0 (amt. of 50% solution needed)
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8-x = 8 gallons (amt. of 25% solution needed)
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Cheers,
Stan H.
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