SOLUTION: How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solutionn to get a 40% solution?

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Question 443233: How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solutionn to get a 40% solution?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
.10x+30(.5)=.4(30+x)
.10x+15=12+.4x
3=.3x
3/.3=x
x=10
You must mix in 10 liters of a 10% solution to get the desired concentration..