SOLUTION: How many liters of pure baking soda must be added to 180 liters of a 40% baking soda solution to get a 70% baking soda solution?

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Question 432501: How many liters of pure baking soda must be added to 180 liters of a 40% baking soda solution to get a 70% baking soda solution?
Found 2 solutions by josmiceli, htmentor:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(liters of pure baking soda in final solution)/(liters of final solution) = 70%
Let x = liters of pure baking soda to be added
given:
Pure baking soda in 40% solution is +.4%2A180+=+72+
-----------------
+%28x+%2B+72%29%2F%28x+%2B+180%29+=+.7+
+x+%2B+72+=+.7%2A%28x+%2B+180%29+
+x+%2B+72+=+.7x+%2B+126+
+.3x+=+54+
+x+=+180+
180 liters of pure baking soda must be added
check:
+%28x+%2B+72%29%2F%28x+%2B+180%29+=+.7+
+%28180+%2B+72%29%2F%28180+%2B+180%29+=+.7+
+252+%2F+360+=+.7+
+.7+=+.7+
OK

Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
The initial amount of baking soda in the 40% solution = 0.40*180 = 72 liters
Let x = the number of liters of baking soda to add
For a 70% solution we have
0.70 = (72+x)/(180+x)
since the same amount, x, is added to the solution and the original amount of baking soda
Solve for x:
0.7(180+x) = 72+x
126 + 0.7x = 72 + x -> 0.3x = 72 -> x = 180 liters
Check:
(72+180)/(180+180) = 252/360 = 0.7