SOLUTION: In a container there are 12 ounces of a solution that is 80% acid. how many ounces of pure water must be added to produce a mixture that is 20% acid solution?
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Question 426354: In a container there are 12 ounces of a solution that is 80% acid. how many ounces of pure water must be added to produce a mixture that is 20% acid solution? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! In a container there are 12 ounces of a solution that is 80% acid. how many ounces of pure water must be added to produce a mixture that is 20% acid solution?
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let x=ounces of pure water to be added.
note that the amount of acid does not change. We are just adding more water to get a weaker concentration of acid.
.80(12)=.2(12+x)
9.6=2.4+.2x
.2x=9.6-2.4=7.2
x=7.2/.2=36
ans
36 ounces of pure water must be added to produce a mixture that is 20% acid solution?
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