SOLUTION: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced?
Log On
Question 424443: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced? Answer by jorel1380(3719) (Show Source):
You can put this solution on YOUR website! 90% sulfuric acid=10% water
.90m+5(1.00)=.5(m+5)
.90m+5=.5m+2.5
.4m=2.5
m=2.5/.4=6.25
You started with 6.25 liters of 90% solution. Add the 5 liters of distilled water, and you have 11.25 liters of a 50% solution..