SOLUTION: In addition to offering the individual types of coffee beans, Crystal sells several special blends. The house favorite, Crystal's Special Blend, contains a combination of French R

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Question 410742: In addition to offering the individual types of coffee beans, Crystal sells several special blends. The house favorite, Crystal's Special Blend, contains a combination of French Roast and Kona Deluxe beans. How many pounds of Kona should she mix with 12lb of French Roast to get a blend to be sold for $10 a pound?
French Roast....$7.50/lb
Kona Deluxe....$ 11.50/lb
please help me I am so confused.
thanks

Found 2 solutions by scott8148, josmiceli:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
this is a fairly standard setup for a mixture problem

(12)($7.50) + (x)($11.50) = (12 + x)($10)

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = pounds of Kona beans needed
In words:
(cost of French Roast in mixture + cost of Kona in mixture) /(total pounds of mixture) =
(cost per pound of mixture)
---------------------
given:
Cost of French roast in mixture = 7.5%2A12+=+90 dollars
Cost of Kona in mixture = 11.5x
Toyal pounds of mixture = 12+%2B+x
-----------------------------
%2890+%2B+11.5x%29%2F%2812+%2B+x%29+=+10%2F1
90+%2B+11.5x+=+10%2A%2812+%2B+x%29
90+%2B+11.5x+=+120+%2B+10x
1.5x+=+30
x+=+20
20 pounds of Kona coffee beans are needed
check answer:
%2890+%2B+11.5x%29%2F%2812+%2B+x%29+=+10%2F1
%2890+%2B+11.5%2A20%29%2F%2812+%2B+20%29+=+10%2F1
%2890+%2B+230%29+%2F+32+=+10
320+=+320
OK