SOLUTION: A car radiator has a 16 quart capacity and is currently filled with a 40% antifreeze solution. How many quarts of this solution must be drained off and replaced with 100% antifree

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Question 401189: A car radiator has a 16 quart capacity and is currently filled with a 40% antifreeze solution. How many quarts of this solution must be drained off and replaced with 100% antifreeze to create a 50% antifreeze solution?
Found 2 solutions by nerdybill, josmiceli:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A car radiator has a 16 quart capacity and is currently filled with a 40% antifreeze solution. How many quarts of this solution must be drained off and replaced with 100% antifreeze to create a 50% antifreeze solution?
.
Let x = amount (quarts) to be drained and replaced
then
.40(16-x) + x = .50(16)
6.4-.40x + x = 8
6.4 + .60x = 8
.60x = 1.6
x = 1.6/.60
x = 2.67 quarts

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In words:
(quarts of antifreeze started with (-) quarts of antifreeze drained off (+) quarts of antifreeze added) / ( final quarts of solution) = 50%
Let x = quarts of solution drained off
Then x = quarts of 100% antifreeze added
given:
16 = final quarts of solution
.4%2A16+=+6.4 = quarts of antifreeze to start with
.4x = quarts of antifreeze drained off
------------------------------------------
%286.4+-.4x+%2B+x%29+%2F+16+=+.5 (note: 16 is really 16+-+x+%2B+x)
6.4+-+.4x+%2B+x+=+16%2A.5
.6x+=+8+-+6.4
.6x+=+1.6
x+=+2.667 quarts
2.667 quarts of 40% solution must be removed and 2.667 quarts of
antifreeze must be added
check answer:
%286.4+-.4%2A%288%2F3%29+%2B+8%2F3%29+%2F+16+=+.5
6.4+-+3.2%2F3++%2B+8%2F3+=+8
3%2A6.4+-+3.2+%2B+8+=+24
19.2+-+3.2+%2B+8+=+24
16+=+16
OK