Question 400904: Here is the problem:
The cooling system of a car has a capacity of 15 liters. If the system is currently filled with a mixture that is 40% antifreeze, how much of this mixture should be drained and replaced with pure antifreeze so that the system is filled with a solution of 50% antifreeze?
I have to 1)define the variables, 2)set up the equation, 3)solve the equation, and 4)answer the question. I am having problems with 1 and 2, defining the variables and setting up the equation. Once I have those I can solve them and answer the questions.
Please help!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! The cooling system of a car has a capacity of 15 liters.
If the system is currently filled with a mixture that is 40% antifreeze,
how much of this mixture should be drained and replaced with pure antifreeze
so that the system is filled with a solution of 50% antifreeze?
:
Let a = amt of pure antifreeze bring the mixture up to 50%
Let a = also amt of existing mixture to be removed
:
The equation (pure antifreeze would be 1a)
.40(15-a) + a = .50(15)
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