SOLUTION: How many liters of a 14% alcohol solution must be mixed with 20L of a 50% solution to get a 30% solution?

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Question 400731: How many liters of a 14% alcohol solution must be mixed with 20L of a 50% solution to get a 30% solution?
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
Let add x liters of a 14% alcohol solution to 20L of a 50% solution, then will have %28x%2B20%29liters of a 30% solution
In x liters of a 14% alcohol solution is 0.14x liters of alcohol
In 20 liters of a 50% alcohol solution is 0.5%2A20=10 liters of alcohol
In %28x%2B20%29 liters of a 30% alcohol solution is 0.3%2A%28x%2B20%29 liters of alcohol
equation
0.14x%2B10=0.3%2A%28x%2B20%29
0.14x%2B10=0.3x%2B6
0.14x-0.3x=6-10
-0.16x=-4
x=%28-4%29%2F%28-0.16%29
x=25liters of a 14% alcohol solution must be mixed with 20L of a 50% solution to get a 30% solution