SOLUTION: A student rode a bicycle to the repair shop and then walked home. The student over aged 14mph riding to the shop and 3.5 mph walking home. The round trip took an hour. How far was
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Question 397092: A student rode a bicycle to the repair shop and then walked home. The student over aged 14mph riding to the shop and 3.5 mph walking home. The round trip took an hour. How far was it between the students home and the bicycle shop? Found 2 solutions by ankor@dixie-net.com, Alan3354:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A student rode a bicycle to the repair shop and then walked home.
The student averaged 14 mph riding to the shop and 3.5 mph walking home.
The round trip took an hour.
How far was it between the students home and the bicycle shop?
:
let d = distance to the repair shop
:
Wrote a time equation; Time = dist/speed
:
to shop time + return time = 1 hr + = 1
:
Multiply by 14, results:
d + 4d = 14
5d = 14
d =
d = 2.8 mi from home to the repair shop
:
:
Check solution by finding the actual times:
2.8/14 = .2 hr
2.8/3.5 =.8 hr
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total time: 1 hr
You can put this solution on YOUR website! There's a shortcut for this, similar to parallel resistors.
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Overall average speed = 2*product/sum
= 2*3.5*14/17.5
= 5.6 mph
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5.6 mph * 1 hour = 5.6 miles RT
= 2.8 miles one way
