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The sum of two numbers is 14
Let x and (14-x) represent the two numbers
Question states***
x^2 + (14-x)^2 = 106
solving for x
2x^2 -28x + 196 = 106
2x^2 -28x + 90 = 0
2(x^2 -14x + 45) = 0
factoring
(x-9)(x-5) = 0 Numbers are 5 and 9
CHECKING our Answer***
25 + 81 = 106