SOLUTION: A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid ounces of 25% alcohol solution. How many fluid ounces of each are needed??

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid ounces of 25% alcohol solution. How many fluid ounces of each are needed??      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 394649: A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid ounces of 25% alcohol solution. How many fluid ounces of each are needed??
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(alcohol)/(fluid) = 25%
Let a = ounces of 20% solution needed
Let b = ounces of 35% solution needed
given:
(1) a+%2B+b+=+60 ounces
.2a+%2B+.35b alcohol in 25% solution
-------------------------------
(2) %28.2a+%2B+.35b%29%2F60+=+.25
(2) .2a+%2B+.35b+=+15
(2) 20a+%2B+35b+=+1500
Multiply both sides of (1) by 20 and
subtract (1) from (2)
(2) 20a+%2B+35b+=+1500
(1) -20a+-+20b+=+-1200
15b+=+300
b+=+20
a+=+60+-+20
a+=+40
40 ounces of 20% solution are needed
20 ounces of 35% solution are needed