SOLUTION: JEN HAS A SOLUTION THAT IS 55% ISOPROPYL ALCOHOL AND A SOLUTION THAT IS 20% ISOPROPYL ALCOHOL. HOW MUCH OF EACH SHOULD SHE USE TO OBTAIN 250 ML OF A SOLUTION THAT IS 41% ISOPROPYL
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Question 393708: JEN HAS A SOLUTION THAT IS 55% ISOPROPYL ALCOHOL AND A SOLUTION THAT IS 20% ISOPROPYL ALCOHOL. HOW MUCH OF EACH SHOULD SHE USE TO OBTAIN 250 ML OF A SOLUTION THAT IS 41% ISOPROPYL ALCOHOL? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! JEN HAS A SOLUTION THAT IS 55% ISOPROPYL ALCOHOL AND A SOLUTION THAT IS 20% ISOPROPYL ALCOHOL. HOW MUCH OF EACH SHOULD SHE USE TO OBTAIN 250 ML OF A SOLUTION THAT IS 41% ISOPROPYL ALCOHOL?
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f = amount of 55%
t = amount of 20%
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f + t = 250 (total volume)
0.55f + 0.2t = 0.41*250 (total alcohol)
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