SOLUTION: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the original solution must be drawn off and replaced by pure antifreeze to make a 25% antifre
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Question 392532: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the original solution must be drawn off and replaced by pure antifreeze to make a 25% antifreeze? Found 2 solutions by stanbon, mananth:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the original solution must be drawn off and replaced by pure antifreeze to make a 25% antifreeze?
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Equation:
alcohol - alcohol + alcohol = alcohol
0.20*16 - 0.20x + 1.00x = 0.25*16
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Multiply thru by 100 to get:
20*16 - 20x + 100x = 25*16
80x = 5*16
x = 5(16/80)
x = 5(1/5)
x = 1 quart (amt. of antifreeze that must be removed and replaced)
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Cheers,
Stan H.
You can put this solution on YOUR website! An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the original solution must be drawn off and replaced by pure antifreeze to make a 25% antifreeze?
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16 quarts of a 20% solution
pure antifreeze 100% x quarts
25% antifreeze mix x+16 quarts
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concentration equation
16*20+100x=25(x+16)
320+100x=25x+400
100x-25x=400-320
75x=80
/75
x= 80/75
x= 1.06 quarts of antifeeze
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m.ananth@hotmail.ca
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