SOLUTION: a company wants a solution of 200 nitogen at 7.7% it has a nitogren mixture of 7% and 8%. how much of each will it need to make the 7.7 % solution

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Question 392016: a company wants a solution of 200 nitogen at 7.7% it has a nitogren mixture of 7% and 8%. how much of each will it need to make the 7.7 % solution
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the required amount of 7% nitrogen(?) mixture, then (200-x) = the required amount of 8% nitrogen mixture. The sum of these two amounts are to equal 200 units of 7.7% nitrogen solution. The equation, after converting the percentages to their decimal eqivalents is:
x%280.07%29%2B%28200-x%29%280.08%29+=+200%280.077%29 Solve for x.
0.07x%2B16-0.08x+=+15.4 Simplify.
-0.01x%2B16+=+15.4 Subtract 16.
-0.01x+=+-0.6 Divide by -0.01
x+=+60
The company will need to mix 60 units of the 7% nitrogen solution with 140 (200-60) units of the 8% nitrogen solution to obtain 200 units of 7.7 nitrogen mixture.