SOLUTION: A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt.

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Question 391849: A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A chemist has one solution that is 30% pure salt and another is 60% pure salt. how many ounces of each solution must he use to produce 60 ounces of a solution that is 50 % salt.
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Equation:
salt + salt = salt
0.30x + 0.60(60-x) = 0.50*60
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Multiply thru by 100 to get:
30x + 60*60-60x = 50*60
-30x = -10*60
x = 20 oz (amt. of 30% solution needed in the mix)
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60-x = 40 oz (amt. of 60% solution needed in the mix)
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Cheers,
stan H.

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
In words:
(salt in final solution)/(salt + water in final solution) = 50%
Let = ounces of 30% solution needed
Let = ounces of 60% solution needed
given:
(1)
= ounces of salt in 30% solution
= ounces of salt in 60% solution
(2)

Substitute this in (1)

and , from (1)

20 ounces of 30% solution are needed
40 ounces of 60% solution are needed
check answer:
(2)
(2)

OK