SOLUTION: How many liters of pure acid must be added to a 6L of a 15% acid solution to obtain a 40% acid solution?

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Question 391255: How many liters of pure acid must be added to a 6L of a 15% acid solution to obtain a 40% acid solution?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = liters of acid to add
given:
.15%2A6+=+.9 liters of acid in 15% solution
----------------
In words:
(liters of acid)/(liters of solution) = 40%
%28a+%2B+.9%29+%2F+%28a+%2B+6%29+=+.4
a+%2B+.9+=+.4%2A%28a+%2B+6%29
a+%2B+.9+=+.4a+%2B+2.4
.6a+=+1.5
a+=+2.5
2.5 liters of pure acid must be added
check answer:
%28a+%2B+.9%29+%2F+%28a+%2B+6%29+=+.4
%282.5+%2B+.9%29+%2F+%282.5+%2B+6%29+=+.4
3.4%2F8.5+=+.4
3.4+=+3.4
OK