SOLUTION: a chemist mixes a solution that is 14% alcohol with a solution that is 22% alcohol to make 200 milliliters of a solution that is 17.6% alcohol. How many milliliters of each solutio

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Question 389463: a chemist mixes a solution that is 14% alcohol with a solution that is 22% alcohol to make 200 milliliters of a solution that is 17.6% alcohol. How many milliliters of each solution does the chemist use in the mixture?
Found 2 solutions by gwendolyn, Fombitz:
Answer by gwendolyn(128) (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 14% alcohol.
Let B be the amount of 22% alcohol.
We know the total amount is 200 ml, so:
A + B = 200
Solving for A (picked at random):
A + B - B = 200 - B
A = 200 - B
Now we form another equation based on the amount of alcohol each solution contributes and the final amount:
.14 * A + .22 * B = .176 * 200
.14A + .22B = 35.2
Multiplying everything by 100 to work with whole numbers:
14*A + 22*B = 3520
Substiture the value of A from the first equation:
14*(200 - B) + 22*B = 3520
2800 - 14*B + 22*B = 3520
2800 + 8*B = 3520
8*B = 3520 - 2800
8*B = 720
B = 90
Substituting the value of B back into the first equation:
A = 200 - B
A = 200 - 90
A = 110

Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 14% alcohol solution, B the amount of 22% solution.
1.
.
.

2.
Multiply eq. 1 by (-7) and add to eq. 2,

ml
Then from eq. 1,

ml