SOLUTION: how much 20% antifreeze solution must be mixed 2with a 80% solution to ptoduce 20 gallons of a 65% disinfecant solution

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Question 388279: how much 20% antifreeze solution must be mixed 2with a 80% solution to ptoduce 20 gallons of a 65% disinfecant solution
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 20% solution, let B be the amount of 80% solution.
1.A%2BB=20
.
.
20A%2B80B=65%2820%29
2.A%2B4B=65
Subtract eq. 1 from eq. 2,
A%2B4B-A-B=65-20
3B=45
highlight%28B=15%29gallons
Then from eq. 1,
A%2B15=20
highlight%28A=5%29gallons