SOLUTION: How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get a 90% acid solution?

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Question 380610: How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get a 90% acid solution?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the amount of the 100% pure acid solution

1.00x + .10*6gal = .90*(x + 6gal)

solving for x

.10x = .80*6gal

x = 48 gal of pure acid needed.



CHECKING our Answer

48gal + .6gal = 48.6gal = .9*54gal = 48.6gal