SOLUTION: A dehydrated patient needs a 6.4% saline IV. Unfortunately, the hospital only has bags of 6% and 8% saline solutions. How many liters of each of these solutions should be mixed tog

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Question 372670: A dehydrated patient needs a 6.4% saline IV. Unfortunately, the hospital only has bags of 6% and 8% saline solutions. How many liters of each of these solutions should be mixed together to yield 1 liter of the desired concentration?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Let x represent the amount of the 8% solution, 

then (1L-x) would be the amount of the 6% solution

.08x + .06(lL -x) = .064*1L

solving for x

.08x + .06*1L - .06x = .064*1L

.02x = .004L

x = .2L of the the 8% solution and .8L of the 6% solution   (1L-.2L)