SOLUTION: How much of 30% HCl and 45% HCl would be needed to mix and produce 50 liters of 35% HCl?

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Question 370172: How much of 30% HCl and 45% HCl would be needed to mix and produce 50 liters of 35% HCl?

Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 30% HCl, B the amount of 45% HCl.
1.A%2BB=50
.
.
30A%2B45B=35%2850%29
2.6A%2B9B=350
Multiply eq. 1 by (-6) and add to eq. 2,
-6A-6B%2B6A%2B9B=-300%2B350
3B=50
highlight%28B=50%2F3%29liters
Then from eq. 1,
A%2B50%2F3=50
A=150%2F3-50%2F3
highlight%28A=100%2F3%29liters

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How much of 30% HCl and 45% HCl would be needed
to mix and produce 50 liters of 35% HCl?
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Equation:
HCL + HCL = HCL
0.30x + 0.45(50-x) = 0.35*50
Multiply thru by 100 to get:
30x + 45*50 - 45x = 35*50
-15x = -10*50
x = (2/3)50
x = 33 1/3 liters (amt. of 30% solution needed in the mixture)
50-x = 16 2/3 liters (amt. of 45% solution needed in the mixture)
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Cheers,
Stan H.
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