SOLUTION: A chemist wants to make 50 mL of a 17% acid solution by mixing a 13% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?

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Question 363211: A chemist wants to make 50 mL of a 17% acid solution by mixing a 13% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?
Found 2 solutions by Fombitz, checkley77:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 13% solution, B the amount of 18% solution.
1.A%2BB=50
.
.
13A%2B18B=17%2850%29
2.13A%2B18B=850
Multiply eq. 1 by (-13) and add to eq. 2,
-13A-13B%2B13A%2B18B=-650%2B850
5B=200
highlight%28B=40%29ml
Then from eq. 1,
A%2B40=50
highlight%28A=10%29ml

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.18x+.13(50-x)=.17*50
.18x+6.5-.13x=8.5
.05x=8.5-6.5
.05x=2
x=2/.05
x=40 ml of 18% acid is used.
Proof:
.18*40+.13(50-40)=.17*50
7.2+.13*10=8.5
7.2+1.3=8.5
8.5=8.5