SOLUTION: please help me solve this problem. a chemist has one solution that is 15% acid and another solution that is 10% acid. how much of the 15% solution is needed to make 80 L of the sol

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Question 363046: please help me solve this problem. a chemist has one solution that is 15% acid and another solution that is 10% acid. how much of the 15% solution is needed to make 80 L of the solution that is 12% acid
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

Let x represent the amount of the 15% solution needed.  

Then (80L-x) would be the amount of 10% solution

.15x + .10(80L-x) = .12*80L

solve for x

.05x = .02*80L

x = 32L of the 15% solution is needed



checking our answer

.15*32L + .10*48 = 4.8 + 4.8 = 9.6