Question 362997: how much water must be mixed with 5 pints of a solution that is 90% developer to produce a mixture that is 39% developer? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! how much water must be mixed with 5 pints of a solution that is 90% developer to produce a mixture that is 39% developer?
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Let x= amount (pints) of water added
then
.90(5) = .39(5+x)
4.5 = 1.95 + .39x
2.55 = .39x
6.54 pints = x (water to be added)
