SOLUTION: how many gallons of an 80% solution and a 20% solution must be mixed to obtain 20 gallons of a 59% solution
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Question 357688
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how many gallons of an 80% solution and a 20% solution must be mixed to obtain 20 gallons of a 59% solution
Answer by
scott8148(6628)
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(x)(80%) + (20 - x)(20%) = (20)(59%)