SOLUTION: how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution?

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Question 355242: how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 20% solution, B the amount of 10% solution.
Total volume:
1.A%2BB=50
.
.
Total concentration:
20A%2B10B=12%2850%29
2.2A%2BB=60
.
.
Subtract eq. 1 from eq. 2,
2A%2BB-A-B=60-50
highlight%28A=10%29liters
Then from eq. 1,
10%2BB=50
highlight%28B=40%29liters