Question 347162: How many liters of water must be added to 30 liters of a 20 percent alcohol solution to dilute it to a 15 percent dilution Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! Hi,
*Note: the 20% tells us how much of the original 30L TOTAL mixture is alcohol!
That is: .20*30L = 6L
That tells us we have 6L of alcohol to use for the New Mixture.
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The question states the new mixture is to be a 15% acohol Mixture
Let M be the TOTAL amount Liters in the new mixture.
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That is: .15*M = 6L
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Solve for M
M = 40L We had 30L, need to add 10L of water.
