SOLUTION: a chemist has two solutions of HCL. One has a 40% concentration and the other one has a 25% concentration. How many liters of each solution must be mixed to obtain 136 Liters of a

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Question 345292: a chemist has two solutions of HCL. One has a 40% concentration and the other one has a 25% concentration. How many liters of each solution must be mixed to obtain 136 Liters of a 33% solution?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let A be the amount of 40% solution and B the amount of 25% solution.
Volume equation:
1.A%2BB=136
.
.
Concentration equation:
40A%2B25B=33%28136%29
2.40A%2B25B=4488
Multiply eq. 1 by (-40) and add to eq. 2,
-40A-40B%2B40A%2B25B=-5440%2B4488%7D%7D%0D%0A%7B%7B%7B-15B=-952
highlight%28B=952%2F15%29liters
.
.
.
Then using eq. 1,
A%2B952%2F15=136
A=2040%2F15-952%2F15
highlight%28A=1088%2F15%29 liters